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If 6 3/m = 4 + 2/n and m = 1/2 , then n =
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28 Oct 2022, 00:37
28 Oct 2022, 00:37
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Question Stats:
41% (00:55) correct
58% (00:50) wrong based on 12 sessions
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If \(6 − \frac{3}{m} = 4 + \frac{2}{n}\) and \(m = \frac{1}{2} \), then \(n = \)
(A) −8
(B) −2
(C) − 1/2
(D) 1/2
(E) 2
(A) −8
(B) −2
(C) − 1/2
(D) 1/2
(E) 2
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GRE Math Essentials (2022)
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GRE Math Essentials (2022)
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GRE - Math Book
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Joined: 02 Jan 2020
Status:GRE Quant Tutor
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Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
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Re: If 6 3/m = 4 + 2/n and m = 1/2 , then n =
[#permalink]
28 Oct 2022, 04:10
28 Oct 2022, 04:10
1
Given that \(6 − \frac{3}{m} = 4 + \frac{2}{n}\) and \(m = \frac{1}{2} \) and we need to find the value of n
Putting \(m = \frac{1}{2} \) in \(6 − \frac{3}{m} = 4 + \frac{2}{n}\) we get
=> \(6 − 3 /\frac{(1}{2) } = 4 + \frac{2}{n}\)
=> \(6 − 3*2 = 4 + \frac{2}{n}\)
=> \(\frac{2}{n}\) = -4
=> n = \(\frac{2}{-4}\) = \(\frac{-1}{2}\)
So, Answer will be C
Hope it helps!
Putting \(m = \frac{1}{2} \) in \(6 − \frac{3}{m} = 4 + \frac{2}{n}\) we get
=> \(6 − 3 /\frac{(1}{2) } = 4 + \frac{2}{n}\)
=> \(6 − 3*2 = 4 + \frac{2}{n}\)
=> \(\frac{2}{n}\) = -4
=> n = \(\frac{2}{-4}\) = \(\frac{-1}{2}\)
So, Answer will be C
Hope it helps!
gmatclubot
Re: If 6 3/m = 4 + 2/n and m = 1/2 , then n = [#permalink]
28 Oct 2022, 04:10
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