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If A = 2x (y 2c) and B = (2x y) 2c, then A B = 2y 4c 0 2y
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25 May 2023, 05:47
25 May 2023, 05:47
Expert Reply
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If A = 2x − (y − 2c) and B = (2x − y) − 2c, then A − B =
A. −2y
B. −4c
C. 0
D. 2y
E. 4c
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A. −2y
B. −4c
C. 0
D. 2y
E. 4c
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) Cracking the GRE Premium
\(\Longrightarrow\) GRE Math Essentials - A most comprehensive handout!!
Re: If A = 2x (y 2c) and B = (2x y) 2c, then A B = 2y 4c 0 2y
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25 May 2023, 09:04
25 May 2023, 09:04
Expert Reply
OE
Because there are variables in the answers, Plug In. Let’s make x = 10, y = 7, and c = 3. Then A = 2 × 10 − (7 − 2 × 3). Solve for the numbers in the parentheses before subtracting: A = 20 − (7 − 6). Therefore, A = 19. B = (2 × 10 − 7) − 2 × 3.
Again, solve for the numbers in the parentheses before subtracting: B = (20 − 7) − 6. Therefore, B = 7. Be careful, the question is asking for A − B = 19 − 7 = 12. Plug y = 7 and c = 3 into the answers. Only (E) yields the target, 12. Choice (C) is a trap designed to catch test takers who subtracted before simplifying the numbers in the parentheses.
Because there are variables in the answers, Plug In. Let’s make x = 10, y = 7, and c = 3. Then A = 2 × 10 − (7 − 2 × 3). Solve for the numbers in the parentheses before subtracting: A = 20 − (7 − 6). Therefore, A = 19. B = (2 × 10 − 7) − 2 × 3.
Again, solve for the numbers in the parentheses before subtracting: B = (20 − 7) − 6. Therefore, B = 7. Be careful, the question is asking for A − B = 19 − 7 = 12. Plug y = 7 and c = 3 into the answers. Only (E) yields the target, 12. Choice (C) is a trap designed to catch test takers who subtracted before simplifying the numbers in the parentheses.
Re: If A = 2x (y 2c) and B = (2x y) 2c, then A B = 2y 4c 0 2y
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25 May 2023, 09:08
25 May 2023, 09:08
Expert Reply
\(A -B\)
\(2x − (y − 2c)\) minus (we change all the signs of the elements of B
\(-2x+y+2c\)
So we do have that \(A-B= 2x − y + 2c -2x+y+2c\)
2x and -2x cancel out
y as well
We left with \(2c+2c=4c\)
E is the answer
\(2x − (y − 2c)\) minus (we change all the signs of the elements of B
\(-2x+y+2c\)
So we do have that \(A-B= 2x − y + 2c -2x+y+2c\)
2x and -2x cancel out
y as well
We left with \(2c+2c=4c\)
E is the answer
