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If a = b × c^2 and c decreases by 20% while a remains : Numeric Entry Question

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Re: If a = b × c^2 and c decreases by 20% while a remains [#permalink]
pranab223 wrote:
Carcass wrote:


If a = b × \(c^2\) and c decreases by 20% while a remains constant, by what percent does b increase?

Round your answer to the nearest 0.1%

enter your value as %
Show: :: OA
56.3



a= bxc^2

Now c is reduced by 20% but a remain constant i.e

a= bx(0.8c)^2 = bx0.64c

therefore b= 1/0.64 = 1.5625

% increase = (1.5625 - 1 )/ 1 x100% = 56.25% ~ 56.3%


Did you assume old value of b as 1?
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Re: If a = b × c^2 and c decreases by 20% while a remains [#permalink]
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Re: If a = b × c^2 and c decreases by 20% while a remains [#permalink]
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