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If a, b, c, and d are consecutive integers
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09 May 2015, 10:25
09 May 2015, 10:25
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Question Stats:
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If a, b, c, and d are consecutive integers such that \(a<b<c<d\), then in terms of a, the sum a + b + d =
(A) \(a + 4\)
(B) \(2a + 3\)
(C) \(3a + 2\)
(D) \(3a + 3\)
(E) \(3a +4\)
Kudos for the right answer and explanation
(A) \(a + 4\)
(B) \(2a + 3\)
(C) \(3a + 2\)
(D) \(3a + 3\)
(E) \(3a +4\)
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
If a, b, c, and d are consecutive integers
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16 May 2015, 15:12
16 May 2015, 15:12
1
sandy wrote:
If a, b, c, and d are consecutive integers such that a<b<c<d, then in terms of a, the sum a + b + d =
(A) a + 4
(B) 2a + 3
(C) 3a + 2
(D) 3a + 3
(E) 3a +4
(A) a + 4
(B) 2a + 3
(C) 3a + 2
(D) 3a + 3
(E) 3a +4
The key here is that a, b, c, and d are CONSECUTIVE integers. So, each integer is 1 GREATER than the one before it.
So, if the 1st integer = a
Then the 2nd integer must = a + 1
The 3rd integer = a + 2
The 4th integer = a + 3
In other words,
a = a
b = a + 1
c = a + 2
d = a + 3
In terms of a, the sum a + b + d =
a + b + d = a + (a + 1) + (a + 3)
= 3a + 4
Answer: E
Cheers,
Brent
Re: If a, b, c, and d are consecutive integers
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11 Dec 2019, 15:32
11 Dec 2019, 15:32
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Bump for further discussion
