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If a brick which is .2 inches by .05 inches by .05 inches is
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30 Jan 2020, 02:23
30 Jan 2020, 02:23
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50% (02:01) correct
50% (02:26) wrong based on 2 sessions
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If a brick which is .2 inches by .05 inches by .05 inches is placed inside a right circular cylinder with a radius of .05 and a height of .2, what portion of the cylinder is not taken up by the brick?
A. \(0.005\pi-0.005\)
B. \(0.0005\pi-0.0005\)
C. \(0.05\pi-0.05\)
D. \(0.0005\pi\)
E. \(0\)
Kudos for the right answer and explanation
A. \(0.005\pi-0.005\)
B. \(0.0005\pi-0.0005\)
C. \(0.05\pi-0.05\)
D. \(0.0005\pi\)
E. \(0\)
Kudos for the right answer and explanation
Re: If a brick which is .2 inches by .05 inches by .05 inches is
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03 Feb 2020, 10:14
03 Feb 2020, 10:14
Volume brick: V = 0,2 * 0,05* 0,05 = 0,0005
volume cylinder: V = r^2 * π * h = 0,05^2 * 2 * π = 0,0005* π
Answer: 0,0005π - 0,0005 = B
volume cylinder: V = r^2 * π * h = 0,05^2 * 2 * π = 0,0005* π
Answer: 0,0005π - 0,0005 = B
gmatclubot
Re: If a brick which is .2 inches by .05 inches by .05 inches is [#permalink]
03 Feb 2020, 10:14
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