GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If a brick which is .2 inches by .05 inches by .05 inches is
[#permalink]
30 Jan 2020, 02:23
30 Jan 2020, 02:23
Expert Reply
00:00
Question Stats:
66% (01:55) correct
33% (02:26) wrong based on 3 sessions
Hide Show timer Statistics
If a brick which is .2 inches by .05 inches by .05 inches is placed inside a right circular cylinder with a radius of .05 and a height of .2, what portion of the cylinder is not taken up by the brick?
A. \(0.005\pi-0.005\)
B. \(0.0005\pi-0.0005\)
C. \(0.05\pi-0.05\)
D. \(0.0005\pi\)
E. \(0\)
Kudos for the right answer and explanation
A. \(0.005\pi-0.005\)
B. \(0.0005\pi-0.0005\)
C. \(0.05\pi-0.05\)
D. \(0.0005\pi\)
E. \(0\)
Kudos for the right answer and explanation
Re: If a brick which is .2 inches by .05 inches by .05 inches is
[#permalink]
03 Feb 2020, 10:14
03 Feb 2020, 10:14
Volume brick: V = 0,2 * 0,05* 0,05 = 0,0005
volume cylinder: V = r^2 * π * h = 0,05^2 * 2 * π = 0,0005* π
Answer: 0,0005π - 0,0005 = B
volume cylinder: V = r^2 * π * h = 0,05^2 * 2 * π = 0,0005* π
Answer: 0,0005π - 0,0005 = B
gmatclubot
Re: If a brick which is .2 inches by .05 inches by .05 inches is [#permalink]
03 Feb 2020, 10:14
Moderators:
