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If a certain toy store's revenue in November was 2/5 of its
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20 Aug 2020, 10:07
20 Aug 2020, 10:07
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Question Stats:
80% (01:24) correct
20% (01:56) wrong based on 30 sessions
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If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?
(A) 1/4
(B) 1/2
(C) 2/3
(D) 2
(E) 4
(A) 1/4
(B) 1/2
(C) 2/3
(D) 2
(E) 4
Re: If a certain toy store's revenue in November was 2/5 of its
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20 Aug 2020, 13:02
20 Aug 2020, 13:02
x= revenue in November
y= revenue in December
z= revenue in January
November's revenue is (2/5) December's revenue. Therefore
x=(2/5)y
January's revenue is (1/4) November's revenue. Therefore
z
=(1/4)x
=(1/4)(2/5)y
=(1/10)y
We are asked for the ratio of December's revenue to the average of November's and January's revenue. That is,
y/((x+z)/2)
= y/[((2/5)y+(1/10)y)/2]
=y/[(5/10)y/2]
=2y/(5/10)y
=2/(5/10)
=20/5
=4
Final Answer: E
y= revenue in December
z= revenue in January
November's revenue is (2/5) December's revenue. Therefore
x=(2/5)y
January's revenue is (1/4) November's revenue. Therefore
z
=(1/4)x
=(1/4)(2/5)y
=(1/10)y
We are asked for the ratio of December's revenue to the average of November's and January's revenue. That is,
y/((x+z)/2)
= y/[((2/5)y+(1/10)y)/2]
=y/[(5/10)y/2]
=2y/(5/10)y
=2/(5/10)
=20/5
=4
Final Answer: E
gmatclubot
Re: If a certain toy store's revenue in November was 2/5 of its [#permalink]
20 Aug 2020, 13:02
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