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If a certain toy store's revenue in November was 2/5 of its revenue in
[#permalink]
09 Aug 2021, 15:32
09 Aug 2021, 15:32
Expert Reply
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Question Stats:
53% (00:58) correct
46% (01:08) wrong based on 13 sessions
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If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?
(A) 1/4
(B) 1/2
(C) 2/3
(D) 2
(E) 4
_________________
(A) 1/4
(B) 1/2
(C) 2/3
(D) 2
(E) 4
_________________
Re: If a certain toy store's revenue in November was 2/5 of its revenue in
[#permalink]
09 Aug 2021, 20:28
09 Aug 2021, 20:28
November's = \(\frac{2}{5}\) December's
January's = \(\frac{1}{4}\) November's
Let's take the revenue in December \(= 100\) so in November, it will be \(40\) and in January \(10\)
Average of November & January = \(\frac{40+10}{2} = 25\)
December's is four times the average.
Answer E
_________________
January's = \(\frac{1}{4}\) November's
Let's take the revenue in December \(= 100\) so in November, it will be \(40\) and in January \(10\)
Average of November & January = \(\frac{40+10}{2} = 25\)
December's is four times the average.
Answer E
_________________
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Re: If a certain toy store's revenue in November was 2/5 of its revenue in
[#permalink]
10 Aug 2021, 19:33
10 Aug 2021, 19:33
1
December revenue=100
November revenue=2*100/5=40
January revenue=1*40/4=10
Required=100:(40+10)/2 = 100:25=4. Answer is E.
November revenue=2*100/5=40
January revenue=1*40/4=10
Required=100:(40+10)/2 = 100:25=4. Answer is E.
Carcass wrote:
If a certain toy store's revenue in November was 2/5 of its revenue in December and its revenue in January was 1/4 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?
(A) 1/4
(B) 1/2
(C) 2/3
(D) 2
(E) 4
(A) 1/4
(B) 1/2
(C) 2/3
(D) 2
(E) 4
gmatclubot
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