We need to find On three consecutive flips of a coin, what is the probability that the coin will land heads up exactly twice in 3 consecutive flips

Coin is tossed 3 times => Total number of cases = $2^3$ = 8

Lets solve the problem using two methods

Method 1:

Out of the 8 cases there are only three cases in which we get exactly two heads. HHT, HTH and THH.

=> Probability of getting exactly two heads = $\frac{3}{8}$ = 0.375

So, Answer will be C

Method 2:

We have three places _ _ _ and we need to find the two places in which we can get a Head. We can do that in 3C2 ways
=> $\frac{3!}{2! * 1!}$ = 3 ways

=> Probability of getting exactly two heads = Number of ways * P(H) * P(H) * P(T) = 3 * $\frac{1}{2}$ * $\frac{1}{2}$ * $\frac{1}{2}$ = $\frac{3}{8}$ = 0.375

So, Answer will be C
Hope it helps!

Watch the following video to learn How to Solve Probability with Coin Toss Problems