Carcass wrote:
If a fair six-sided die with faces numbered 1 through 6 is tossed 3 times, what is the probability of getting a 1 or a 2 on all three tosses?
Kudos for the right answer and explanation
There are 6 possible outcomes when rolling a die: 1, 2, 3, 4, 5, 6
So, P(1 or 2) = 2/6 =
1/3We want the probability of getting a 1 or a 2 on all three tosses
P(1 or a 2 on all three tosses) = P(1 or 2 on 1st toss
AND 1 or 2 on 2nd toss
AND 1 or 2 on 3rd toss)
= P(1 or 2 on 1st toss)
x P(1 or 2 on 2nd toss)
x P(1 or 2 on 3rd toss)
=
1/3 x 1/3 x 1/3= 1/27
Answer: 1/27
Cheers,
Brent