GeminiHeat wrote:
If a number N is chosen at random from the set of two-digit integers whose digits are both prime numbers, what is the probability that N is divisible by 3?
A. 1/3
B. 1/4
C. 9/25
D. 5/16
E. 0
Let the number be \((a)(b)\)
possible values of \(a\) = 4 (2, 3 ,5, 7)
possible values of \(b\) = 4 (2, 3 ,5, 7)
Total possible 2-digit numbers = \((4)(4) = 16\)
Now, numbers divisible by 3;
2(7), 3(3), 5(7), 7(2), 7(5)
Required Probability = \(\frac{5}{16}\)
Hence, option D