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Re: If a triangle in the xy-coordinate system has vertices at [#permalink]
High 10 base 30 ?

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Re: If a triangle in the xy-coordinate system has vertices at [#permalink]
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tagedwedw wrote:
High 10 base 30 ?

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No, Height 10
Base 6

Area = \(\frac{1}{2}*6*10=30\)

Originally posted by AE on 07 Jan 2019, 19:53.
Last edited by AE on 08 Jan 2019, 16:56, edited 1 time in total.
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Re: If a triangle in the xy-coordinate system has vertices at [#permalink]
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Carcass wrote:
If a triangle in the xy-coordinate system has vertices at (– 2, –3), (4, –3) and (28, 7), what is the area of the triangle?

A. 30

B. 36

C. 48

D. 60

E. 65



(-2,-3) and (4,-3) is a straight line parallel to x axis at y=-3. Therefore let's take this as the base..so Base = 4-(-2)=4+2=6..

Now the third vertice is (28,7)..
If we are taking base as parallel to x-axis , the height will be parallel to y-axis.
Therefore height is 7-(-3)=7+3=10

Area will be \(\frac{1}{2}*6*10=30\)

A
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Re: If a triangle in the xy-coordinate system has vertices at [#permalink]
chetan2u wrote:


(-2,-3) and (4,-3) is a straight line parallel to y axis at y=-3. Therefore let's take this as the base..so Base = 4-(-2)=4+2=6..


Is it parallel to y axis or x axis? Please make it clear.
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Re: If a triangle in the xy-coordinate system has vertices at [#permalink]
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AE wrote:
chetan2u wrote:


(-2,-3) and (4,-3) is a straight line parallel to y axis at y=-3. Therefore let's take this as the base..so Base = 4-(-2)=4+2=6..


Is it parallel to y axis or x axis? Please make it clear.


y=-3 will be parallel to z-axis.
Thanks edited
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Re: If a triangle in the xy-coordinate system has vertices at [#permalink]
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