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If a2 + b2 = 18 and ab = 6, then (a - b)2 =
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02 Mar 2022, 04:00
02 Mar 2022, 04:00
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Question Stats:
71% (00:45) correct
28% (01:39) wrong based on 14 sessions
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If \(a^2 + b^2 = 18\) and \(ab = 6\), then \((a - b)^2 = \)
(A) -12
(B) -6
(C) 0
(D) 6
(E) 12
(A) -12
(B) -6
(C) 0
(D) 6
(E) 12
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Re: If a2 + b2 = 18 and ab = 6, then (a - b)2 =
[#permalink]
02 Mar 2022, 06:15
02 Mar 2022, 06:15
1
Carcass wrote:
If \(a^2 + b^2 = 18\) and \(ab = 6\), then \((a - b)^2 = \)
(A) -12
(B) -6
(C) 0
(D) 6
(E) 12
(A) -12
(B) -6
(C) 0
(D) 6
(E) 12
Given: a² + b² = 18
Given: ab = 6
We want to find the value of: (a - b)²
In other words, we want to find the value of: (a - b)(a - b)
Expand to get: a² - 2ab + b²
Rearrange to get: a² + b² - 2ab
Substitute values to get: 18 - 2(6), which evaluates to be 6
Answer: D
gmatclubot
Re: If a2 + b2 = 18 and ab = 6, then (a - b)2 = [#permalink]
02 Mar 2022, 06:15
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