OE According to the problem, AB = BD. Therefore, triangle ABD is an isosceles triangle, and angle BAD is equal to x. Additionally, since you know angle AD E = 90 and angle DAE = 30, you can determine that angle AED = 180 - 90 - 30 = 60 (since these three angles form the triangle ADE). You can update the diagram as follows:
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The angles of the large triangle, ACE, must sum to 180. Therefore, 70 + 60 + 30 + x = 180, so x = 20. Since y, x, and x must sum to 180 (they form the angles of triangle ABD), y = 180 - 2x, so y = 140. Thus, the correct ratio is 20/140