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General Discussion
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Re: If AD = BC, find the value of x [#permalink]
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himanshu13 wrote:
Hi, I am a bit confused here, hope you guys can help :

What if I start with angle DBC = 90-x, then
2x+90-x+dcb = 180
dcb = 90-x
this will make DB=DC

and then if i continue, I get x = 60

Please help guys


Everything you wrote this correct. I'm just not sure how you got x = 60.
Can you elaborate on how you x = 60?

It turns out that triangle DBC is an equilateral triangle.
This means 2x = 60, in which case x = 30
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Re: If AD = BC, find the value of x [#permalink]
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himanshu13

Hi

The steps are correct indeed.

You seriously puzzled my brain. Pls let me know how u got angle x as 60. how did u continued?
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Re: If AD = BC, find the value of x [#permalink]
I'm little confused too. How could you conclude that ∠BAD = x°?
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Re: If AD = BC, find the value of x [#permalink]
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GR3A wrote:
I'm little confused too. How could you conclude that ∠BAD = x°?


Let's focus on triangle ABD below:
Image

We already know that two of the angles in this triangle are x and (180 - 2x)
The only missing angle is ∠BAD

Since the three angles in a triangle must add to 180°, we can write: x + (180 - 2x) + ∠BAD = 180
Simplify: 180 - x + ∠BAD = 180
Subtract 180 from both sides: -x + ∠BAD = 0
Add x to both sides: ∠BAD = x

Does that help?
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Re: If AD = BC, find the value of x [#permalink]
Tt does really. Thanks a lot Brent
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Re: If AD = BC, find the value of x [#permalink]
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