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If all the grades are evenly distributed through- out all di
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25 Jul 2020, 09:33
25 Jul 2020, 09:33
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45% (01:56) correct
54% (02:41) wrong based on 24 sessions
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GRE What is the approximate ratio of students earning a C to those earning a B.jpg [ 100.29 KiB | Viewed 4845 times ]
If all the grades are evenly distributed throughout all districts and classes, approximately how many students in De Beque are not earning a B?
A. 20
B. 40
C. 70
D. 100
E. 115
Intern
Joined: 25 Jul 2020
Posts: 38
Given Kudos: 0
GRE 1: Q170 V157
Re: If all the grades are evenly distributed through- out all di
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25 Jul 2020, 11:20
25 Jul 2020, 11:20
The first step is to find the proportion of non-B grades. This can be done by finding (A + C + D + F)/(A + B + C + D + F), which for me was about 0.59.
Then just multiply: 0.59*115 = 68.17, and 70 is the closest to it. Note that A is a grade that isn't B, so that does have to be included.
Then just multiply: 0.59*115 = 68.17, and 70 is the closest to it. Note that A is a grade that isn't B, so that does have to be included.
Re: If all the grades are evenly distributed through- out all di
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04 Aug 2020, 03:48
04 Aug 2020, 03:48
2
The number of students in De Beque not earning a B = All of the students in De Beque minus those earning a B
Since the grades are evenly distributed among the different districts, the number of B's De Beque will get will correspond to the weight De Beque represents among the total number of students
namely, 115/1105
De Beque gets 115/1105 of all B's
Therefore the number of B's De Beque gets is = (115/1105)*450 = around 47
Final answer is 115-47= 68
Which is close to 70.
Final Answer: C
Since the grades are evenly distributed among the different districts, the number of B's De Beque will get will correspond to the weight De Beque represents among the total number of students
namely, 115/1105
De Beque gets 115/1105 of all B's
Therefore the number of B's De Beque gets is = (115/1105)*450 = around 47
Final answer is 115-47= 68
Which is close to 70.
Final Answer: C
