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If Beth has more money than Ari, and each person has an inte
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Updated on: 25 Mar 2020, 14:54

Expert Reply

4

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Question Stats:

If Beth has \(\frac{1}{4}\) MORE money than Ari, and each person has an integer number of dollars, which of the following could be the combined value of Beth and Ari's money?

Indicate all such values.

A. $12

B. $54

C. $72

D. $200

_________________

Indicate all such values.

A. $12

B. $54

C. $72

D. $200

_________________

Sandy

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Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
19 Aug 2018, 06:58

2

sandy wrote:

If Beth has more money than Ari, and each person has an integer number of dollars, which of the following could be the combined value of Beth and Ari’s money?

Indicate all such values.

A. $12

B. $54

C. $72

D. $200

Indicate all such values.

A. $12

B. $54

C. $72

D. $200

I think something else is required to ans the question. As it is it can be any combination for getting the four options. such as 1+11, 1+53, 2+70, 99 + 101

_________________

Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
25 Mar 2020, 14:39

Any updates on this? No way the answer is correct per the question.

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
25 Mar 2020, 14:51

Expert Reply

let me find out it, if something is wrong.

Back soon

_________________

Back soon

_________________

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
25 Mar 2020, 14:55

1

Expert Reply

\(B=A+(\frac{A}{4})\)

\(B=\frac{5A}{4}\)

\(\frac{A}{B}=\frac{5n}{4n}\)

The TOTAL amount of money must be a multiple of \(9n (5n+4n)\). So 54 and 72 work.

_________________

\(B=\frac{5A}{4}\)

\(\frac{A}{B}=\frac{5n}{4n}\)

The TOTAL amount of money must be a multiple of \(9n (5n+4n)\). So 54 and 72 work.

_________________

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
25 Mar 2020, 14:56

1

Expert Reply

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
17 Oct 2020, 17:28

2

B = (5/4 )* A

A+B = A + (5/4) * A = (9/4)* A , now put the values, the answer is 54 and 72 only

A+B = A + (5/4) * A = (9/4)* A , now put the values, the answer is 54 and 72 only

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
20 Dec 2020, 02:53

May someone help me find out what is my mistake ?

B=1.25A

So, the sum is A+1.25A=2.25A

so the answer must be divided by 2.25 and give us an integer. The correct answer is 72. But wrong.

B=1.25A

So, the sum is A+1.25A=2.25A

so the answer must be divided by 2.25 and give us an integer. The correct answer is 72. But wrong.

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
16 Jan 2021, 19:48

2

1

Bookmarks

If Beth has 1/4 MORE money than Ari, and each person has an integer number of dollars, which of the following could be the combined value of Beth and Ari's money?

the question is asking about combined value of the 2 people, Total = B+A ==>(1)

B alone = A+1/4A ==> B= 5/4A==>(2)

Substitute b with the first equation ==> Total= 5/4A+A==> Total = 9/4A

the only answers is 54 and 72

the question is asking about combined value of the 2 people, Total = B+A ==>(1)

B alone = A+1/4A ==> B= 5/4A==>(2)

Substitute b with the first equation ==> Total= 5/4A+A==> Total = 9/4A

the only answers is 54 and 72

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
16 Jan 2021, 21:30

1

Asmakan wrote:

May someone help me find out what is my mistake ?

B=1.25A

So, the sum is A+1.25A=2.25A

so the answer must be divided by 2.25 and give us an integer. The correct answer is 72. But wrong.

B=1.25A

So, the sum is A+1.25A=2.25A

so the answer must be divided by 2.25 and give us an integer. The correct answer is 72. But wrong.

The correct ans is B and C. Both 54 and 72 when divided by 2.25 gives an integer value.

_________________

Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos

If Beth has more money than Ari, and each person has an inte
[#permalink]
09 Sep 2021, 20:56

B = A + A/4 = 5A/4

A + B = A + 5A/4 = 9A/4

Total = 9A/4 = 9/4 * A

The least possible value of A is 4 to make the total value an integer.

So, Total = 9/4 * 4 = 9. The answer will be 9 or the multiples of 9.

Ans: B, C

A + B = A + 5A/4 = 9A/4

Total = 9A/4 = 9/4 * A

The least possible value of A is 4 to make the total value an integer.

So, Total = 9/4 * 4 = 9. The answer will be 9 or the multiples of 9.

Ans: B, C

Re: If Beth has more money than Ari, and each person has an inte
[#permalink]
19 Jul 2023, 06:25

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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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