Carcass wrote:
If both expressions \(x^2 – 3x + 2\) and \(x^2 – 4x + 3\) equal 0, then what is the value of \((x – 3)^2\) ?
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
Since, both expressions equals to
zero then we can rewrite as
\(x^2 – 3x + 2\) = \(x^2 – 4x + 3\)
or x = 1
Now, using the value of x in the equation,
\((x – 3)^2\) = \((1 – 3)^2\) = \((2)^2\) =
4