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If each number of a sequence is 4 more than the previous number, and
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09 Feb 2021, 09:35
09 Feb 2021, 09:35
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If each number of a sequence is 4 more than the previous number, and the 3rd number in the sequence is 13, what is the 114th number in the sequence?
A. 117
B. 257
C. 444
D. 457
E. 477
A. 117
B. 257
C. 444
D. 457
E. 477
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If each number of a sequence is 4 more than the previous number, and
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09 Feb 2021, 22:38
09 Feb 2021, 22:38
1
GeminiHeat wrote:
If each number of a sequence is 4 more than the previous number, and the 3rd number in the sequence is 13, what is the 114th number in the sequence?
A. 117
B. 257
C. 444
D. 457
E. 477
A. 117
B. 257
C. 444
D. 457
E. 477
The sequence would be: x, x+4, x+8, x+12, ..... [Arithmetic Progression with common difference of 4]
Third term = x+8 = 13
So, First term = x = 5
Apply the formula of A.P to find the \(n^{th}\) term;
\(T_n\) = a + (n-1)d
\(T_{114}\) = 5 + (114-1) x 4 = 457
Hence, option D
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If each number of a sequence is 4 more than the previous number, and
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31 Dec 2024, 00:54
31 Dec 2024, 00:54
1
If each number of a sequence is 4 more than the previous number, and the 3rd number in the sequence is 13
This is an Arithmetic Series with
Third term, \(T_{3}\) = 13
Common difference, d = 4
Using, \(T_n\) = a + (n-1)*d
\(T_3\) = a + (3-1)*4 = a + 2*4 = a + 8 = 13
=> a = 13 - 8 = 5
What is the 114th number in the sequence?
\(T_{114}\) = 5 + (114-1)*4 = 5 + 113*4 = 5 + 452 = 457
So, Answer will be D
Hope it helps!
Watch the following video to MASTER Sequence problems
This is an Arithmetic Series with
Third term, \(T_{3}\) = 13
Common difference, d = 4
Using, \(T_n\) = a + (n-1)*d
\(T_3\) = a + (3-1)*4 = a + 2*4 = a + 8 = 13
=> a = 13 - 8 = 5
What is the 114th number in the sequence?
\(T_{114}\) = 5 + (114-1)*4 = 5 + 113*4 = 5 + 452 = 457
So, Answer will be D
Hope it helps!
Watch the following video to MASTER Sequence problems
