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If f(x) = 1/(x+2) +(x-1)^2, what is f(-1)?
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09 Feb 2021, 09:58
09 Feb 2021, 09:58
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Question Stats:
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If \(f(x) = \frac{1}{x+2} +(x-1)^2\), what is \(f(-1)\)?
A. 1
B. 3
C. 5
D. 7
E. 9
A. 1
B. 3
C. 5
D. 7
E. 9
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Re: If f(x) = 1/(x+2) +(x-1)^2, what is f(-1)?
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09 Feb 2021, 22:31
09 Feb 2021, 22:31
1
GeminiHeat wrote:
If \(f(x) = \frac{1}{x+2} +(x-1)^2\), what is \(f(-1)\)?
A. 1
B. 3
C. 5
D. 7
E. 9
A. 1
B. 3
C. 5
D. 7
E. 9
Simply plug x = -1 in f(x) to get 5
Hence, option C
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Re: If f(x) = 1/(x+2) +(x-1)^2, what is f(-1)?
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18 Jan 2022, 10:07
18 Jan 2022, 10:07
1
Given that \(f(x) = \frac{1}{x+2} +(x-1)^2\) and we need to find the value of \(f(-1)\)
To find f(-1) we need to compare f(-1) with f(x) and see what is inside the bracket of f()
=> x=-1
=> To find the value of f(-1) we need to replace x with -1 in \(f(x) = \frac{1}{x+2} +(x-1)^2\)
=> \(f(-1) = \frac{1}{-1+2} +(-1-1)^2\) = \(\frac{1}{1} +(-2)^2\) = 1 + 4 = 5
So, Answer will be C
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
To find f(-1) we need to compare f(-1) with f(x) and see what is inside the bracket of f()
=> x=-1
=> To find the value of f(-1) we need to replace x with -1 in \(f(x) = \frac{1}{x+2} +(x-1)^2\)
=> \(f(-1) = \frac{1}{-1+2} +(-1-1)^2\) = \(\frac{1}{1} +(-2)^2\) = 1 + 4 = 5
So, Answer will be C
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
