edited/misreading the question
Out all unit digits only 2 and 8 will square to the unit's digit equal to 4.
When \((k+1)^2\) has unit's digit 1, this will imply k has unit's digit added by 1. Out of (2+1) and (8+1) choices, only 8 will be the right choice. The unit's digit of \((k + 2)^2\) is 0, as \((8+2)^2=100\) Answer is
A Carcass wrote:
If k is a positive integer, and if the units’ digit of \(k^2\) is 4 and the units’ digit of \((k + 1)^2\) is 1, what is the units’ digit of \((k + 2)^2\) ?
(A) 0
(B) 2
(C) 4
(D) 6
(E) 8