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If k is a positive integer, then (8^k)^ 2 =
[#permalink]
04 Jan 2022, 06:49
04 Jan 2022, 06:49
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20% (00:44) wrong based on 10 sessions
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If k is a positive integer, then \((8^k)^ 2 = \)
(A) \(2^{8k} \)
(B) \(8^{k + 2} \)
(C) \(4^{4k} \)
(D) \(2^{6k} \)
(E) \(16^k \)
Kudos for the right answer and explanation
See more on this topic Exponents
(A) \(2^{8k} \)
(B) \(8^{k + 2} \)
(C) \(4^{4k} \)
(D) \(2^{6k} \)
(E) \(16^k \)
Kudos for the right answer and explanation
See more on this topic Exponents
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Joined: 10 Apr 2015
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Re: If k is a positive integer, then (8^k)^ 2 =
[#permalink]
04 Jan 2022, 07:00
04 Jan 2022, 07:00
1
Carcass wrote:
If k is a positive integer, then \((8^k)^ 2 = \)
(A) \(2^{8k} \)
(B) \(8^{k + 2} \)
(C) \(4^{4k} \)
(D) \(2^{6k} \)
(E) \(16^k \)
Kudos for the right answer and explanation
See more on this topic Exponents
(A) \(2^{8k} \)
(B) \(8^{k + 2} \)
(C) \(4^{4k} \)
(D) \(2^{6k} \)
(E) \(16^k \)
Kudos for the right answer and explanation
See more on this topic Exponents
Key property: \((b^x)^y = b^{xy}\)
So we get: \((8^k)^ 2 = 8^{2k} \)
Check the answer choices....\(8^{2k}\) isn't there.
So, we'll have to rewrite \(8^{2k}\)
Let's rewrite \(8\) as \(2^3 \), and plug this into our expression to get: \((2^3)^{2k}\)
Apply the above property again to get: \(2^{6k}\)
Answer: D
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Re: If k is a positive integer, then (8^k)^ 2 = [#permalink]
04 Jan 2022, 07:00
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