Last visit was: 21 Nov 2024, 05:23 It is currently 21 Nov 2024, 05:23

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 29998
Own Kudos [?]: 36326 [0]
Given Kudos: 25922
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 29998
Own Kudos [?]: 36326 [0]
Given Kudos: 25922
Send PM
User avatar
Senior Manager
Senior Manager
Joined: 10 Feb 2020
Posts: 496
Own Kudos [?]: 348 [0]
Given Kudos: 299
Send PM
avatar
Manager
Manager
Joined: 22 Jan 2020
Posts: 120
Own Kudos [?]: 240 [0]
Given Kudos: 10
Send PM
Re: If m is an integer such that (-2)^2m = 2^{9 - m}, then m= [#permalink]
1
Farina wrote:
Since base is same so,
2m = 9 - m
2m+m = 9
3m = 9
m = 3

Just wondering about minus sign with 2 in question stem. We have to ignore it?



The base is not the same.
The base of the first one is -2 for the LHS and 2 for the RHS.
But since the LHS is raised to an even power the negative doesn't matter and we can treat it as 2 instead of -2

Why? B/c

(-2)^2m = ((-1)(2))^2m = (-1)^2m * (2)^2m = ((-1)^2)^m * (2)^2m = 1^m * (2)^2m = 1 * (2)^2m = (2)^2m
User avatar
Senior Manager
Senior Manager
Joined: 10 Feb 2020
Posts: 496
Own Kudos [?]: 348 [0]
Given Kudos: 299
Send PM
Re: If m is an integer such that (-2)^2m = 2^{9 - m}, then m= [#permalink]
chacinluis wrote:
Farina wrote:
Since base is same so,
2m = 9 - m
2m+m = 9
3m = 9
m = 3

Just wondering about minus sign with 2 in question stem. We have to ignore it?



The base is not the same.
The base of the first one is -2 for the LHS and 2 for the RHS.
But since the LHS is raised to an even power the negative doesn't matter and we can treat it as 2 instead of -2

Why? B/c

(-2)^2m = ((-1)(2))^2m = (-1)^2m * (2)^2m = ((-1)^2)^m * (2)^2m = 1^m * (2)^2m = 1 * (2)^2m = (2)^2m


Thank you very much for clarification
Prep Club for GRE Bot
Re: If m is an integer such that (-2)^2m = 2^{9 - m}, then m= [#permalink]
Moderators:
GRE Instructor
83 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne