m is the square of integer n and m is divisible by 98

Let's do prime factorization of 98 we get, 98 = 2*\(7^2\)
Since, m is a square of an integer and m is divisible by 98
That means that m must be a multiple of 98
=> m = 98*k (where k is an integer)
=> m = 2*\(7^2\) * k
Now, for m to be square of a number minimum value of k should be 2. (As this will make m a perfect square)
=> m = \(2^2\) *\(7^2\) = \(14^2\) = 196

So, m will be divisible by 28 and 196 and not by 343

So, Answer will be C
Hope it helps!