motion2020 wrote:
If \(m\), \(n\), \(p\), and \(q\) are distinct positive integers, greater than \(1\) such that \(mnpq=660\), how many
possible combination of values exist for \(m\), \(n\), \(p\), and \(q\) ?
(A) Two
(B) Three
(C) Four
(D) Five
(E) Seven
Source: Manhattan Review, GMAT Question Bank
The prime factorization of 660 gives \(2^2,3,5\) and \(11\). So for set of 4 distinct combinations, there could be only 4,
(4,3,5,11),(2,6,5,11),(2,3,10,11) and (2,3,5,22).
Answer is C) Four