GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If n =9 sqrt 1/x^4
[#permalink]
09 Aug 2021, 02:02
09 Aug 2021, 02:02
Expert Reply
00:00
Question Stats:
89% (00:42) correct
10% (01:04) wrong based on 19 sessions
Hide Show timer Statistics
If \(n =9 \sqrt{\frac{1}{x^4}}\), what is the value of \(\sqrt{n}\) ?
A. \(\frac{1}{3x}\)
B. \(\frac{3}{x}\)
C. \(\frac{3}{x^2}
\)
D. \(\frac{9}{x}
\)
E. \(\frac{9}{x^2}\)
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
A. \(\frac{1}{3x}\)
B. \(\frac{3}{x}\)
C. \(\frac{3}{x^2}
\)
D. \(\frac{9}{x}
\)
E. \(\frac{9}{x^2}\)
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
If n =9 sqrt 1/x^4
[#permalink]
09 Aug 2021, 02:37
09 Aug 2021, 02:37
1
Solution:
\(9 \sqrt{\frac{1}{x^4}}\)= \(9 \sqrt{\frac{1}{{x* x* x*x}}}\)
Finding the square root of \(\sqrt{{\frac{1}{x^4}}}\)
n= \(9{\frac{1}{x^2}}\)
Square rooting both sides we get
\(\sqrt{n}\)= \(3 {\frac{1}{x^2}}\)= \( {\frac{3}{x^2}}\)
IMO B
We can also solve this question by substituting value of x.
Hope this helps!
\(9 \sqrt{\frac{1}{x^4}}\)= \(9 \sqrt{\frac{1}{{x* x* x*x}}}\)
Finding the square root of \(\sqrt{{\frac{1}{x^4}}}\)
n= \(9{\frac{1}{x^2}}\)
Square rooting both sides we get
\(\sqrt{n}\)= \(3 {\frac{1}{x^2}}\)= \( {\frac{3}{x^2}}\)
IMO B
We can also solve this question by substituting value of x.
Hope this helps!
gmatclubot
If n =9 sqrt 1/x^4 [#permalink]
09 Aug 2021, 02:37
Moderators:
