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If n divided by 35 has a remainder of 3, what is the remainder when n
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18 Feb 2021, 04:16
18 Feb 2021, 04:16
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If n divided by 35 has a remainder of 3, what is the remainder when n is divided by 7?
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Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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3
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: If n divided by 35 has a remainder of 3, what is the remainder when n
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18 Feb 2021, 06:41
18 Feb 2021, 06:41
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Carcass wrote:
\(Number = (Divisor)(Quotient) + Remainder\)
\(n = 35Q + 3\)
Q can be 1, 2, 3, ....
When Q = 1, n = 38
When Q = 2, n= 73 and so on
We can clearly see,
When 38 is divided by 7, the remainder is 3
When 73 is divided by 7, the remainder is 3
So, the remainder would be 3
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Re: If n divided by 35 has a remainder of 3, what is the remainder when n
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22 Jul 2021, 04:48
22 Jul 2021, 04:48
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If N divided by D equals Q with remainder R, then:
N = DQ + R
Hence, n = 35k + 3.
Let's assume that k = 1. Then, we have the number 38.
38/7 will give us a remainder of 3.
Bonus: this can be easily determined on a calculator by dividing 38 by 7, taking only the decimal component, and multiplying that by 7 (the divisor in this case).
Hence, the remainder is 3.
N = DQ + R
Hence, n = 35k + 3.
Let's assume that k = 1. Then, we have the number 38.
38/7 will give us a remainder of 3.
Bonus: this can be easily determined on a calculator by dividing 38 by 7, taking only the decimal component, and multiplying that by 7 (the divisor in this case).
Hence, the remainder is 3.
