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If n is a multiple of 15^2 x 20^3, which of the following is not
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16 Jul 2023, 23:08
16 Jul 2023, 23:08
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30% (01:47) correct
69% (02:28) wrong based on 13 sessions
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If n is a multiple of \(15^2 X 20^3\), which of the following is not necessarily an integer?
Indicate all that apply
A. \(\frac{n}{5000}\)
B. \(\frac{n}{7500}\)
C. \(\dfrac{3000}{\sqrt{n}}\)
D. \(\dfrac{\sqrt{n}}{200}\)
E. \(\dfrac{n-n^3}{n-1}\)
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\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
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Indicate all that apply
A. \(\frac{n}{5000}\)
B. \(\frac{n}{7500}\)
C. \(\dfrac{3000}{\sqrt{n}}\)
D. \(\dfrac{\sqrt{n}}{200}\)
E. \(\dfrac{n-n^3}{n-1}\)
Post A Detailed Correct Solution For The Above Questions And Get Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE NUMBER PROPERTIES
Re: If n is a multiple of 15^2 x 20^3, which of the following is not
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17 Jul 2023, 05:41
17 Jul 2023, 05:41
1
15^2 x 20^3 can be prime factorised as 5^5 x 3^2 x 2^6. For choice A n/5000, 5000 can be factored as 5 x (5x2)^3 which is fully divisible by n, hence not correct. Choice B n/7500 7500 can be factored as 5^4 x 3^1 x 2^2 which is fully divisible by n, hence not correct. Choice C 3000/n^1/2, n is not a perfect square because 5 has an odd power hence the root of n will not be an integer. 3000/n^1/2 will not be an integer. Choice D follows similar logic, n^1/2 /200 will not be an integer. Choice E can be simplified to 1-n^3 , which will be a negative integer, hence not correct.
Answer: C,D
Answer: C,D
gmatclubot
Re: If n is a multiple of 15^2 x 20^3, which of the following is not [#permalink]
17 Jul 2023, 05:41
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