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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2508
Given Kudos: 1053
GPA: 3.39
If n is a positive integer, then (-2^n)^{-2} + (2^{-n})^2 is equal to
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25 Nov 2021, 04:04
25 Nov 2021, 04:04
Expert Reply
4
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00:00
Question Stats:
40% (01:42) correct
59% (01:11) wrong based on 22 sessions
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If n is a positive integer, then \((-2^{n})^{-2}\) +\((2^{-n})^{2}\) =
A. 0
B. \(2^{(-2n)}\)
C. \(2^{(2n)}\)
D. \(2^{(-2n+1)}\)
E. \(2^{(2n+1)}\)
A. 0
B. \(2^{(-2n)}\)
C. \(2^{(2n)}\)
D. \(2^{(-2n+1)}\)
E. \(2^{(2n+1)}\)
Re: If n is a positive integer, then (-2^n)^{-2} + (2^{-n})^2 is equal to
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26 Nov 2021, 06:09
26 Nov 2021, 06:09
Expert Reply
-2^(-2n) + 2^(-2n) = 1/4^n + 1/4^n = 2/2^2n = 2^(1 - 2n)
Answer: D
Answer: D
Re: If n is a positive integer, then (-2^n)^{-2} + (2^{-n})^2 is equal to
[#permalink]
12 Jul 2024, 05:00
12 Jul 2024, 05:00
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