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If one number is chosen at random from the first 1,000 positive inte
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23 Jul 2021, 10:18
23 Jul 2021, 10:18
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If one number is chosen at random from the first 1,000 positive integers, what is the probability that the number chosen is multiple of both 2 and 8?
A. 1/125
B. 1/8
C. 1/2
D. 9/16
E. 5/8
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
A. 1/125
B. 1/8
C. 1/2
D. 9/16
E. 5/8
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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If one number is chosen at random from the first 1,000 positive inte
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23 Jul 2021, 11:19
23 Jul 2021, 11:19
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Carcass wrote:
If one number is chosen at random from the first 1,000 positive integers, what is the probability that the number chosen is multiple of both 2 and 8?
A. 1/125
B. 1/8
C. 1/2
D. 9/16
E. 5/8
A. 1/125
B. 1/8
C. 1/2
D. 9/16
E. 5/8
Since 2 is a factor of 8, every multiple of 8 will be a multiple of 2
Let us find the number of Multiples of 8 from 1-1000;
Multiple of a number n = \(\frac{L - F}{n} + 1\)
Where, L = Last number divisible by n in given terms
F = First number divisible by n in given terms
So, Multiples of 8 =\(\frac{1000 - 8}{8} + 1 = 125\)
Required probability = \(\frac{125}{1000} = \frac{1}{8}\)
Hence, option B
Re: If one number is chosen at random from the first 1,000 positive inte
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15 Aug 2024, 21:28
15 Aug 2024, 21:28
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