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If p > 0 and 0 < 1 ( ) < 1, then which of the following must be tru
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Updated on: 10 Sep 2024, 10:13
Updated on: 10 Sep 2024, 10:13
Expert Reply
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Question Stats:
80% (01:42) correct
20% (02:30) wrong based on 10 sessions
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If \( p > 0\) and \(0 < 1 – (\frac{ q}{p }) < 1\), then which of the following must be true?
A. \(p>q\)
B. \(q>0\)
C. \(\frac{q}{p}<1\)
D. \(\frac{p}{q}<1\)
A. \(p>q\)
B. \(q>0\)
C. \(\frac{q}{p}<1\)
D. \(\frac{p}{q}<1\)
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Re: If p > 0 and 0 < 1 ( ) < 1, then which of the following must be tru
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10 Sep 2024, 09:45
10 Sep 2024, 09:45
Explanation?
Re: If p > 0 and 0 < 1 ( ) < 1, then which of the following must be tru
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10 Sep 2024, 10:20
10 Sep 2024, 10:20
1
Expert Reply
Sorry there was a typo in the inequality \(0 < 1 – (\frac{ q}{p }) < 1\)
It was q/p and NOT p/q
Now
\(0 < 1 – (\frac{ q}{p }) < 1\)
A is p>q this is true because iF for example q/p and q>p such as 3/2 then -1/3 will be between 0 and 1 and this is nOT possible. Therefore, A must be true
B . q>0 this is also must be true because otherwise the fraction q/p would be undefined and this is not possible on the GRE. Such as 0/3
C. we do know also that the fraction q/p must be also <1 and this is also true.
D the reverse p/q the reverse clearly is not possible. It is also implied in A
I hope this helps
It was q/p and NOT p/q
Now
\(0 < 1 – (\frac{ q}{p }) < 1\)
A is p>q this is true because iF for example q/p and q>p such as 3/2 then -1/3 will be between 0 and 1 and this is nOT possible. Therefore, A must be true
B . q>0 this is also must be true because otherwise the fraction q/p would be undefined and this is not possible on the GRE. Such as 0/3
C. we do know also that the fraction q/p must be also <1 and this is also true.
D the reverse p/q the reverse clearly is not possible. It is also implied in A
I hope this helps
