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Re: If p ≠ 0 and p = (2pq − q^2)^(1/2), then in terms of q, p =
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06 Mar 2021, 07:11
1
Carcass wrote:
If p ≠ 0 and \(p = \sqrt{2pq − q^2}\), then in terms of q, p =
(A) q (B) q^2 (C) 2q (D) –2q (E) q/4
Given: \(p = \sqrt{2pq − q^2}\) Square both sides to get: p² = 2pq - q² Set equation equal to zero: p² - 2pq + q² = 0 [NOTE: I did this because we have a quadratic equation] Factor: (p - q)(p - q) = 0 So, we can conclude that p - q = 0, which means p = q
Re: If p 0 and p = (2pq q^2)^(1/2), then in terms of q, p =
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16 Feb 2024, 14:37
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