GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If p ≠ 0 and p = (2pq − q^2)^(1/2), then in terms of q, p =
[#permalink]
06 Mar 2021, 06:42
06 Mar 2021, 06:42
Expert Reply
00:00
Question Stats:
78% (01:27) correct
21% (01:17) wrong based on 32 sessions
Hide Show timer Statistics
If p ≠ 0 and \(p = \sqrt{2pq − q^2}\), then in terms of q, p =
(A) q
(B) q^2
(C) 2q
(D) –2q
(E) q/4
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
(A) q
(B) q^2
(C) 2q
(D) –2q
(E) q/4
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If p ≠ 0 and p = (2pq − q^2)^(1/2), then in terms of q, p =
[#permalink]
06 Mar 2021, 07:11
06 Mar 2021, 07:11
1
Carcass wrote:
If p ≠ 0 and \(p = \sqrt{2pq − q^2}\), then in terms of q, p =
(A) q
(B) q^2
(C) 2q
(D) –2q
(E) q/4
(A) q
(B) q^2
(C) 2q
(D) –2q
(E) q/4
Given: \(p = \sqrt{2pq − q^2}\)
Square both sides to get: p² = 2pq - q²
Set equation equal to zero: p² - 2pq + q² = 0 [NOTE: I did this because we have a quadratic equation]
Factor: (p - q)(p - q) = 0
So, we can conclude that p - q = 0, which means p = q
Answer: A
Cheers,
Brent
Moderator
Joined: 02 Jan 2020
Status:GRE Quant Tutor
Posts: 1141
Given Kudos: 9
Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
Re: If p 0 and p = (2pq q^2)^(1/2), then in terms of q, p =
[#permalink]
03 Sep 2022, 04:16
03 Sep 2022, 04:16
1
Given that p ≠ 0 and \(p = \sqrt{2pq − q^2}\) and we need to find the value of p in terms of q
\(p = \sqrt{2pq − q^2}\)
Squaring both the sides we get
\(p^2 = (\sqrt{2pq − q^2})^2\)
=> \(p^2 = 2pq − q^2\)
=> \(p^2 - 2pq + q^2\) = 0
=> \((p-q)^2\) = 0
=> p = q
So, Answer will be A
Hope it helps!
\(p = \sqrt{2pq − q^2}\)
Squaring both the sides we get
\(p^2 = (\sqrt{2pq − q^2})^2\)
=> \(p^2 = 2pq − q^2\)
=> \(p^2 - 2pq + q^2\) = 0
=> \((p-q)^2\) = 0
=> p = q
So, Answer will be A
Hope it helps!
