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If p = 216–1/3 + 243–2/5 + 256–1/4, then which one of the fo
[#permalink]
16 Apr 2019, 01:31
16 Apr 2019, 01:31
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Expert Reply
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Question Stats:
66% (01:52) correct
33% (02:39) wrong based on 12 sessions
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If \(p = 216^{–\frac{1}{3}} + 243^{–\frac{2}{5}} + 256^{–\frac{1}{4}}\), then which one of the following is an integer?
(A) \(\frac{p}{19}\)
(B) \(\frac{p}{36}\)
(C) \(p\)
(D) \(\frac{19}{p}\)
(E) \(\frac{36}{p}\)
(A) \(\frac{p}{19}\)
(B) \(\frac{p}{36}\)
(C) \(p\)
(D) \(\frac{19}{p}\)
(E) \(\frac{36}{p}\)
Re: If p = 216–1/3 + 243–2/5 + 256–1/4, then which one of the fo
[#permalink]
15 Apr 2020, 12:00
15 Apr 2020, 12:00
Expert Reply
P= 1/6+ 1/9 + 1/4
=19/36
Therefore 19/p=36(which is an integer)
D is the answer
=19/36
Therefore 19/p=36(which is an integer)
D is the answer
gmatclubot
Re: If p = 216–1/3 + 243–2/5 + 256–1/4, then which one of the fo [#permalink]
15 Apr 2020, 12:00
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