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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
If p pounds of beef cost d dollars, how many cents would k pounds of b
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07 Jan 2023, 09:40
07 Jan 2023, 09:40
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If p pounds of beef cost d dollars, how many cents would k pounds of beef cost after the price had been reduced by c cents per pound?
A. \((\frac{d - cp}{p})k\)
B. \((\frac{d - cp}{100p})k\)
C. \((\frac{d - 100cp}{100p})k\)
D. \((\frac{100d - cp}{p})k\)
E. \((\frac{100d - 100cp}{p})k\)
A. \((\frac{d - cp}{p})k\)
B. \((\frac{d - cp}{100p})k\)
C. \((\frac{d - 100cp}{100p})k\)
D. \((\frac{100d - cp}{p})k\)
E. \((\frac{100d - 100cp}{p})k\)
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Re: If p pounds of beef cost d dollars, how many cents would k pounds of b
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08 Jan 2023, 10:36
08 Jan 2023, 10:36
Expert Reply
Asked: If p pounds of beef cost d dollars, how many cents would k pounds of beef cost after the price had been reduced by c cents per pound?
Price per pound of beef = d/p
Price after reduction of c cents per pound = (d/p - c/100)
Price in cents of k pounds of beef after price reduction = k100(d/p - c/100) = k/p (100d - cp)
Answer: D
Price per pound of beef = d/p
Price after reduction of c cents per pound = (d/p - c/100)
Price in cents of k pounds of beef after price reduction = k100(d/p - c/100) = k/p (100d - cp)
Answer: D
Target Test Prep Representative
Joined: 12 Sep 2018
Status:Founder & CEO, Target Test Prep
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Given Kudos: 5
Re: If p pounds of beef cost d dollars, how many cents would k pounds of b
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13 Apr 2023, 06:42
13 Apr 2023, 06:42
1
Expert Reply
GeminiHeat wrote:
If p pounds of beef cost d dollars, how many cents would k pounds of beef cost after the price had been reduced by c cents per pound?
A. \((\frac{d - cp}{p})k\)
B. \((\frac{d - cp}{100p})k\)
C. \((\frac{d - 100cp}{100p})k\)
D. \((\frac{100d - cp}{p})k\)
E. \((\frac{100d - 100cp}{p})k\)
A. \((\frac{d - cp}{p})k\)
B. \((\frac{d - cp}{100p})k\)
C. \((\frac{d - 100cp}{100p})k\)
D. \((\frac{100d - cp}{p})k\)
E. \((\frac{100d - 100cp}{p})k\)
The price of beef in dollars, per pound, is d/p. In cents, the price per pound is 100d/p. When we reduce the price by c cents per pound, we have:
100d/p - cp/p = (100d - cp)/p
Thus, k pounds costs:
k(100d - cp)/p
Answer: D
