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If q is even, then #q = –2; If q is odd, then #q = –4. a and
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26 Mar 2018, 15:58
26 Mar 2018, 15:58
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Question Stats:
46% (01:09) correct
53% (01:04) wrong based on 30 sessions
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If q is even, then #q = –2;
If q is odd, then #q = –4.
a and b are integers such that b – 3 is odd.
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
If q is odd, then #q = –4.
a and b are integers such that b – 3 is odd.
Quantity A |
Quantity B |
#(6a) |
#b |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Drill 1
Question: 10
Page: 550-551
Question: 10
Page: 550-551
Re: If q is even, then #q = –2; If q is odd, then #q = –4. a and
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29 Mar 2018, 06:52
29 Mar 2018, 06:52
What is the value of #q if q is zero?
if a = 0 then what ?
if a = 0 then what ?
Re: If q is even, then #q = –2; If q is odd, then #q = –4. a and
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06 Apr 2018, 15:07
06 Apr 2018, 15:07
Expert Reply
Explanation
Rather than trying to remember a bunch of rules about even and odd numbers, Plug In for a and b. If a is 2, then 6a is 12, and #12 = –2.
Because b – 3 is odd, make b = 6, and #b = –2 as well. The two quantities are equal, so eliminate choices (A) and (B).
Any set of values gives the same outcome, so select choice (C).
Rather than trying to remember a bunch of rules about even and odd numbers, Plug In for a and b. If a is 2, then 6a is 12, and #12 = –2.
Because b – 3 is odd, make b = 6, and #b = –2 as well. The two quantities are equal, so eliminate choices (A) and (B).
Any set of values gives the same outcome, so select choice (C).
