Carcass wrote:
If \(\sqrt{x+6} + \sqrt{x+1}=5\) what is the value of \(x^2\)?
A. 1
B. 4
C. 9
D. 16
E. 25
Source:
manhattanreviewRather than try to solve this tricky equation, a much faster approach is to
test the answer choices.A. 1
If x² = 1, then x = 1 or -1
If x = 1, we have: \(\sqrt{0+6} + \sqrt{0+1}=5\). Doesn't work!
If x = -1, we have: \(\sqrt{(-1)+6} + \sqrt{(-1)+1}=5\). Doesn't work!
B. 4
If x² = 4, then x = 2 or -2
If x = 2, we have: \(\sqrt{2+6} + \sqrt{2+1}=5\). Doesn't work!
If x = -2, we have: \(\sqrt{(-2)+6} + \sqrt{(-2)+1}=5\). Doesn't work!
C. 9
If x² = 9, then x = 3 or -3
If x = 3, we have: \(\sqrt{3+6} + \sqrt{3+1}=5\). WORKS!!!
Answer: C