\(\frac{x + y + z + 5 + 7}{5} = 8\)

x + y + z = 40 - 12 = 28

When, x = 1
y + z = 27

I. The median of the five numbers cannot be 5 - NO
x = 1, y = 2, z = 25
Terms in ascending order: 1, 2, 5, 7, 25, Median = 5

II. At least one of x, y and z is greater than 9
Since, they add up to 28, one of them has to be greater than 9

III The range of the five numbers is 2 or more

In order to minimize the range, let us maximize y and z
x = 1, y = 13, z = 14
Terms in ascending order: 1, 5, 7, 13, 14, Range = 13

Hence, option E