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If the product of the integers w, x, y and z is 770, and if 1 < w < x
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24 Jun 2021, 08:52
24 Jun 2021, 08:52
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Question Stats:
94% (01:11) correct
5% (00:42) wrong based on 19 sessions
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If the product of the integers w, x, y and z is 770, and if 1 < w < x < y < z, what is the value of w + z?
A. 10
B. 13
C. 16
D. 18
E. 21
A. 10
B. 13
C. 16
D. 18
E. 21
Re: If the product of the integers w, x, y and z is 770, and if 1 < w < x
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24 Jun 2021, 09:17
24 Jun 2021, 09:17
1
\(wxyz = 770\) & \(1 < w < x < y < z\)
770 = 2 * 5 * 7 * 11
\(w = 2 , x = 5 , y = 7 , z = 11\)
\(w + z = 13\)
Answer B
770 = 2 * 5 * 7 * 11
\(w = 2 , x = 5 , y = 7 , z = 11\)
\(w + z = 13\)
Answer B
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Re: If the product of the integers w, x, y and z is 770, and if 1 < w < x
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24 Jun 2021, 09:23
24 Jun 2021, 09:23
1
Carcass wrote:
If the product of the integers w, x, y and z is 770, and if 1 < w < x < y < z, what is the value of w + z?
A. 10
B. 13
C. 16
D. 18
E. 21
A. 10
B. 13
C. 16
D. 18
E. 21
This looks like a job for prime factorization!
770 = (2)(5)(7)(11)
If 1 < w < x < y < z, then we can see that w = 2, x = 5, y = 7 and z = 11
So, w + z = 2 + 11 = 13
Answer: B
Cheers,
Brent
