Carcass wrote:
If the radius of a circle were increased by 5 feet, the area of the circular region would increase by 65π square feet. What is the radius, in feet, before the increase?
(A) 4
(B) 8
(C) 9
(D) 13
(E) 18
Let r = radius of ORIGINAL circle
Area = π(radius)²
So, area of ORIGINAL circle =
πr²If the radius of a circle were increased by 5 feet....So, r + 5 = radius of NEW circle
Area of NEW circle =
π(r + 5)²...the area of the circular region would increase by 65π square feet.(area of NEW circle) = (area of ORIGINAL circle) + 65π
In other words,
π(r + 5)² =
πr² + 65π
Divide both sides by π to get: (r + 5)² = r² + 65
Expand and simplify left side: r² + 10r + 25 = r² + 65
Subtract r² from both sides to get: 10r + 25 = 65
Subtract 25 from both sides to get: 10r = 40
Solve: r = 4
What is the radius, in feet, before the increase?Answer = 4
= A
Cheers,
Brent