GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If u and –3v are greater than 0, and
[#permalink]
12 Aug 2018, 10:09
12 Aug 2018, 10:09
Expert Reply
3
Bookmarks
00:00
Question Stats:
44% (02:01) correct
55% (01:38) wrong based on 153 sessions
Hide Show timer Statistics
If u and –3v are greater than 0, and \(\sqrt{u} < \sqrt{-3v}\) , which of the following cannot be true ?
A. \(\frac{u}{3} < -v\)
B. \(\frac{u}{v} > -3\)
C. \(\sqrt{\frac{u}{-v}} < \sqrt{3}\)
D. \(u + 3v > 0\)
E. \(u < -3v\)
A. \(\frac{u}{3} < -v\)
B. \(\frac{u}{v} > -3\)
C. \(\sqrt{\frac{u}{-v}} < \sqrt{3}\)
D. \(u + 3v > 0\)
E. \(u < -3v\)
Re: If u and –3v are greater than 0, and
[#permalink]
18 Aug 2018, 20:24
18 Aug 2018, 20:24
2
1
Bookmarks
Carcass wrote:
If u and –3v are greater than 0, and \(\sqrt{u} < \sqrt{-3v}\) , which of the following cannot be true ?
A. \(\frac{u}{3} < -v\)
B. \(\frac{u}{v} > -3\)
C. \(\sqrt{\frac{u}{-v}} < \sqrt{3}\)
D. \(u + 3v > 0\)
E. \(u < -3v\)
A. \(\frac{u}{3} < -v\)
B. \(\frac{u}{v} > -3\)
C. \(\sqrt{\frac{u}{-v}} < \sqrt{3}\)
D. \(u + 3v > 0\)
E. \(u < -3v\)
A quick glance through all the option, we will see that
option D which is \(u + 3v > 0\) is not possible, so might be the answer, however lets look at the remaing option
option A :: \(\frac{u}{3} < -v\) - This is possible if we divide by 3 on both sides
Option B:: \(\frac{u}{v} > -3\) - This is possible, since -3v > 0 so v < 0
Option C:: \(\sqrt{\frac{u}{-v}} < \sqrt{3}\) - It is possible by dividing \(\sqrt{-v}\) on both sides
Option E:: \(u < -3v\) - It is also possible by squaring on both sides.
** When the GRE writes a root sign, they are indicating a nonnegative root only**
Re: If u and –3v are greater than 0, and
[#permalink]
25 May 2019, 07:33
25 May 2019, 07:33
here, u>0, and -3v>0
So, u+(-3v)>0
U-3v >0
But, option D is not as above . So, D.
So, u+(-3v)>0
U-3v >0
But, option D is not as above . So, D.
