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If u and –3v are greater than 0, and
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12 Aug 2018, 10:09
12 Aug 2018, 10:09
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54% (01:30) wrong based on 129 sessions
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If u and –3v are greater than 0, and \(\sqrt{u} < \sqrt{-3v}\) , which of the following cannot be true ?
A. \(\frac{u}{3} < -v\)
B. \(\frac{u}{v} > -3\)
C. \(\sqrt{\frac{u}{-v}} < \sqrt{3}\)
D. \(u + 3v > 0\)
E. \(u < -3v\)
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A. \(\frac{u}{3} < -v\)
B. \(\frac{u}{v} > -3\)
C. \(\sqrt{\frac{u}{-v}} < \sqrt{3}\)
D. \(u + 3v > 0\)
E. \(u < -3v\)
_________________
Re: If u and –3v are greater than 0, and
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18 Aug 2018, 20:24
18 Aug 2018, 20:24
2
Carcass wrote:
If u and –3v are greater than 0, and \(\sqrt{u} < \sqrt{-3v}\) , which of the following cannot be true ?
A. \(\frac{u}{3} < -v\)
B. \(\frac{u}{v} > -3\)
C. \(\sqrt{\frac{u}{-v}} < \sqrt{3}\)
D. \(u + 3v > 0\)
E. \(u < -3v\)
A. \(\frac{u}{3} < -v\)
B. \(\frac{u}{v} > -3\)
C. \(\sqrt{\frac{u}{-v}} < \sqrt{3}\)
D. \(u + 3v > 0\)
E. \(u < -3v\)
A quick glance through all the option, we will see that
option D which is \(u + 3v > 0\) is not possible, so might be the answer, however lets look at the remaing option
option A :: \(\frac{u}{3} < -v\) - This is possible if we divide by 3 on both sides
Option B:: \(\frac{u}{v} > -3\) - This is possible, since -3v > 0 so v < 0
Option C:: \(\sqrt{\frac{u}{-v}} < \sqrt{3}\) - It is possible by dividing \(\sqrt{-v}\) on both sides
Option E:: \(u < -3v\) - It is also possible by squaring on both sides.
** When the GRE writes a root sign, they are indicating a nonnegative root only**
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Re: If u and –3v are greater than 0, and
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25 May 2019, 07:33
25 May 2019, 07:33
here, u>0, and -3v>0
So, u+(-3v)>0
U-3v >0
But, option D is not as above . So, D.
So, u+(-3v)>0
U-3v >0
But, option D is not as above . So, D.
Re: If u and –3v are greater than 0, and
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26 May 2019, 07:37
26 May 2019, 07:37
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Carcass wrote:
If u and –3v are greater than 0, and \(\sqrt{u} < \sqrt{-3v}\) , which of the following cannot be true ?
A. \(\frac{u}{3} < -v\)
B. \(\frac{u}{v} > -3\)
C. \(\sqrt{\frac{u}{-v}} < \sqrt{3}\)
D. \(u + 3v > 0\)
E. \(u < -3v\)
A. \(\frac{u}{3} < -v\)
B. \(\frac{u}{v} > -3\)
C. \(\sqrt{\frac{u}{-v}} < \sqrt{3}\)
D. \(u + 3v > 0\)
E. \(u < -3v\)
If \(\sqrt{u} < \sqrt{-3v}\), then it must also be true that u < -3v
Scan the answer choices....
Hmmm, D says that u + 3v > 0
However, if we take u < -3v and add 3v to both sides, we get: u + 3v < 0, which is the OPPOSITE of what answer choice D is saying.
Answer: D
Cheers,
Brent
_________________
Re: If u and –3v are greater than 0, and
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21 Apr 2020, 09:30
21 Apr 2020, 09:30
** When the GRE writes a root sign, they are indicating a nonnegative root only**
Can someone explain what is the exact meaning of this with an example?
Thanks in advance!
Can someone explain what is the exact meaning of this with an example?
Thanks in advance!
Re: If u and –3v are greater than 0, and
[#permalink]
21 Apr 2020, 09:44
21 Apr 2020, 09:44
1
ZIONGRE wrote:
** When the GRE writes a root sign, they are indicating a nonnegative root only**
Can someone explain what is the exact meaning of this with an example?
Thanks in advance!
Can someone explain what is the exact meaning of this with an example?
Thanks in advance!
Every positive number has two square roots.
For example, the square root of 25 is 5, since 5² = 25 AND -5, since (-5)² = 25
However, the square root NOTATION tells us to indicate the non-negative root only.
So, for example:
\(\sqrt{25}=5\)
\(\sqrt{49}=7\)
\(\sqrt{0.25}=0.5\)
\(\sqrt{0}=0\)
etc
Does that help?
Cheers,
Brent
_________________
Re: If u and 3v are greater than 0, and
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30 May 2023, 22:08
30 May 2023, 22:08
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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