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GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
If x= 1/(2^2*3^2*4^2*5^2) is expressed as a decimal, how many distinct
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22 Apr 2022, 07:56
22 Apr 2022, 07:56
Expert Reply
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Question Stats:
65% (01:44) correct
35% (00:58) wrong based on 20 sessions
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If x= 1/(2^2*3^2*4^2*5^2) is expressed as a decimal, how many distinct nonzero digits will x have?
A. One
B. Two
C. Three
D. Seven
E. Ten
A. One
B. Two
C. Three
D. Seven
E. Ten
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Re: If x= 1/(2^2*3^2*4^2*5^2) is expressed as a decimal, how many distinct
[#permalink]
26 Apr 2022, 09:47
26 Apr 2022, 09:47
2
1
Expert Reply
\(\frac{1}{(2^2*3^2*4^2*5^2)}\) = \(\frac{1}{2^2} * \frac{1}{3^2} * \frac{1}{4^2} * \frac{1}{5^2}= \frac{1}{100} * \frac{1}{9} * \frac{1}{16}\)
= \((.01 * .0625) * \frac{1}{9}\) (division by 9 leads to a non-terminating decimal so leave it for the end)
= .000625/9
= .0000694444...
So we have 3 distinct non-zero digits.
Answer (C)
= \((.01 * .0625) * \frac{1}{9}\) (division by 9 leads to a non-terminating decimal so leave it for the end)
= .000625/9
= .0000694444...
So we have 3 distinct non-zero digits.
Answer (C)
Re: If x= 1/(2^2*3^2*4^2*5^2) is expressed as a decimal, how many distinct
[#permalink]
24 May 2023, 10:16
24 May 2023, 10:16
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