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WE:Education (Education)
If [m]x + [fraction]1/x[/fraction] = 3[/m], then [m]x^5 + [fraction]1/
[#permalink]
11 Mar 2021, 01:44
11 Mar 2021, 01:44
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Question Stats:
50% (03:23) correct
50% (02:26) wrong based on 12 sessions
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If \(x + \frac{1}{x} = 3\), then \(x^5 + \frac{1}{x^5} = ?\)
A. 0
B. 4
C. 120
D. 123
E. 126
A. 0
B. 4
C. 120
D. 123
E. 126
Re: If [m]x + [fraction]1/x[/fraction] = 3[/m], then [m]x^5 + [fraction]1/
[#permalink]
11 Mar 2021, 20:34
11 Mar 2021, 20:34
1
(x+1/x)2 = x2 + 1/x2 +2 = 9
x2+1/x2 = 7
(x+1/x)3 = x3+3x+3/x+x3 = 27
x3+1/x3 = 18
(x2+1/x2)(x3+1/x3) = 126
x5+1/x5 + (x+1/x) = 126
x5+ 1/x5 = 123
x2+1/x2 = 7
(x+1/x)3 = x3+3x+3/x+x3 = 27
x3+1/x3 = 18
(x2+1/x2)(x3+1/x3) = 126
x5+1/x5 + (x+1/x) = 126
x5+ 1/x5 = 123
Re: If [m]x + [fraction]1/x[/fraction] = 3[/m], then [m]x^5 + [fraction]1/
[#permalink]
03 Sep 2024, 00:40
03 Sep 2024, 00:40
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