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If x–2 – 2 = –1.96, y1/3 – 5 = –2, and xy > 0, then what is
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18 Mar 2018, 06:40
18 Mar 2018, 06:40
Expert Reply
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Question Stats:
90% (04:30) correct
10% (02:50) wrong based on 20 sessions
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If \(x^{-2} - 2 = -1.96\), \(y^{\frac{1}{3}} - 5 = -2\), and xy > 0, then what is the value of xy ?
Drill 2
Question: 15
Page: 499
Question: 15
Page: 499
Show: :: OA
135
Re: If x–2 – 2 = –1.96, y1/3 – 5 = –2, and xy > 0, then what is
[#permalink]
21 Mar 2018, 14:11
21 Mar 2018, 14:11
Expert Reply
Explanation
First solve for x: Add 2 to both sides to yield \(x^{-2}\) = 0.04, so \(\frac{1}{x^2}=\frac{1}{25}\), and x =±5.
Next, add 5 to both sides of the other equation to yield \(y^{1/3} = 3\), so \(\sqrt[3]{y}= 3\), and y = 27.
Since y is positive, you’ll need to use the positive value of x as well, so 5 × 27 = 135.
First solve for x: Add 2 to both sides to yield \(x^{-2}\) = 0.04, so \(\frac{1}{x^2}=\frac{1}{25}\), and x =±5.
Next, add 5 to both sides of the other equation to yield \(y^{1/3} = 3\), so \(\sqrt[3]{y}= 3\), and y = 27.
Since y is positive, you’ll need to use the positive value of x as well, so 5 × 27 = 135.
gmatclubot
Re: If x–2 – 2 = –1.96, y1/3 – 5 = –2, and xy > 0, then what is [#permalink]
21 Mar 2018, 14:11
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