Last visit was: 25 Apr 2024, 05:26 It is currently 25 Apr 2024, 05:26
Decision Tracker
My Rewards
New comers' posts
New posts
Unanswered

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more
Close

Request Expert Reply

Confirm Cancel
PREVIOUS TOPIC
NEXT TOPIC

If |x-2|<4 then the solution set will be

Tags :
Find Similar Topics  About  Add a Tag

Show Tags
Hide Tags

User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 28634
Own Kudos [?]: 33115 [3]
Given Kudos: 25175
Send PM
If |x-2|<4 then the solution set will be [#permalink] New post   Updated on: 29 Jun 2021, 10:13
Expert Reply
3
Bookmarks
00:00

Question Stats:

42% (00:40) correct 57% (00:54) wrong based on 33 sessions

Hide Show timer Statistics

If \(|x-2| \leq 4\) then the solution set will be

Select all that apply

A. \(2 \leq x \leq 6\)

B. \(-2 \leq x \leq 6
\)

C. \(2 \leq x \leq -6\)

D. \(-2 \leq x \leq -6\)

E. \(2 \geq - x \geq - 6\)


Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
ShowHide Answer
Official Answer
B,E

Originally posted by Carcass on 19 Apr 2021, 12:48.
Last edited by Carcass on 29 Jun 2021, 10:13, edited 1 time in total.
Updated
User avatar
D
KarunMendiratta
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Own Kudos [?]: 2942 [1]
Given Kudos: 172
Location: India
WE:Education (Education)
Send PM
Re: If |x-2|<4 then the solution set will be [#permalink] New post   20 Apr 2021, 22:55
1
Carcass wrote:
If \(|x-2| \leq 4\) then the solution set will be

Select all that apply

A. \(2 \leq x \leq 6\)

B. \(-2 \leq x \leq 6
\)

C. \(2 \leq x \leq -6\)

D. \(-2 \leq x \leq -6\)

E. \(2 \geq x \geq 6\)


Carcass
Can you please check the option choices again?
User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 28634
Own Kudos [?]: 33115 [0]
Given Kudos: 25175
Send PM
Re: If |x-2|<4 then the solution set will be [#permalink] New post   20 Apr 2021, 23:21
Expert Reply
They are correct
User avatar
D
KarunMendiratta
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Own Kudos [?]: 2942 [0]
Given Kudos: 172
Location: India
WE:Education (Education)
Send PM
Re: If |x-2|<4 then the solution set will be [#permalink] New post   20 Apr 2021, 23:28
Carcass wrote:
They are correct


\(2 ≥ x ≥ 6\)

How come 2 is greater than x which is greater than 6?
avatar
S
void
Senior Manager
Senior Manager
Joined: 03 Dec 2020
Posts: 440
Own Kudos [?]: 59 [1]
Given Kudos: 68
Send PM
Re: If |x-2|<4 then the solution set will be [#permalink] New post   21 Apr 2021, 01:19
1
plz explain option e...how it is correct...
User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 28634
Own Kudos [?]: 33115 [0]
Given Kudos: 25175
Send PM
Re: If |x-2|<4 then the solution set will be [#permalink] New post   21 Apr 2021, 03:12
Expert Reply
KarunMendiratta wrote:
Carcass wrote:
They are correct


\(2 ≥ x ≥ 6\)

How come 2 is greater than x which is greater than 6?


You are right. maybe a typo

From logic it must be -6

I fixed in the answer choices. Now have to be fine

Many Thanks

Regards
avatar
keerthana15
Intern
Intern
Joined: 08 Feb 2021
Posts: 3
Own Kudos [?]: 1 [0]
Given Kudos: 12
Send PM
Re: If |x-2|<4 then the solution set will be [#permalink] New post   27 Jun 2021, 23:21
how the option E is correct
avatar
G
taskforce
Manager
Manager
Joined: 19 Feb 2021
Posts: 184
Own Kudos [?]: 173 [0]
Given Kudos: 425
GRE 1: Q170 V170
Send PM
Re: If |x-2|<4 then the solution set will be [#permalink] New post   30 Jun 2021, 04:37
For Option E, if you multiply it with the negative sign then you will get the same set as that of option B.
When you multiply the inequality with the negative sign make sure you flip the inequalities.
So it will become -2<=x<=6
User avatar
D
KarunMendiratta
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Own Kudos [?]: 2942 [1]
Given Kudos: 172
Location: India
WE:Education (Education)
Send PM
Re: If |x-2|<4 then the solution set will be [#permalink] New post   30 Jun 2021, 06:17
1
taskforce wrote:
For Option E, if you multiply it with the negative sign then you will get the same set as that of option B.
When you multiply the inequality with the negative sign make sure you flip the inequalities.
So it will become -2<=x<=6


|x - 2| ≤ 4

Case I:
x - 2 ≤ 4
x ≤ 6

Case II:
-(x - 2) ≤ 4
-x + 2 ≤ 4
-x ≤ 2

Multiplying both sides by -1 [The inequality will flip];
x ≥ -2

Therefore, x must lie between -2 and 6
i.e. -2 ≤ x ≤ 6

On multiplying by -1, it will be
2 ≥ -x ≥ -6

Hence, option B and E
Prep Club for GRE Bot
gmatclubot
[#permalink]
Moderators:
BrushMyQuant
Moderator
1085 posts
VibhuAnurag
GRE Instructor
218 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Main navigation

Partners

GRE Resources

www.ets.org/gre | About | Terms and Conditions and Privacy Policy | Prep Club for GRE Rules | Contact