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If (x+2)(x-5)/(x-3)(x+4)=1, then x=
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24 Feb 2020, 14:51
24 Feb 2020, 14:51
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Question Stats:
83% (01:09) correct
16% (01:56) wrong based on 31 sessions
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If \(\frac{(x+2)(x-5)}{(x-3)(x+4)}=1\), then \(x=\)
A. \(-2\)
B. \(- \frac{1}{2}\)
C. \(1\)
D. \(\frac{1}{2}\)
E. \(2\)
Kudos for the right answer and explanation
A. \(-2\)
B. \(- \frac{1}{2}\)
C. \(1\)
D. \(\frac{1}{2}\)
E. \(2\)
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If (x+2)(x-5)/(x-3)(x+4)=1, then x=
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25 Feb 2020, 07:33
25 Feb 2020, 07:33
2
Carcass wrote:
If \(\frac{(x+2)(x-5)}{(x-3)(x+4)}=1\), then \(x=\)
A. \(-2\)
B. \(- \frac{1}{2}\)
C. \(1\)
D. \(\frac{1}{2}\)
E. \(2\)
Kudos for the right answer and explanation
A. \(-2\)
B. \(- \frac{1}{2}\)
C. \(1\)
D. \(\frac{1}{2}\)
E. \(2\)
Kudos for the right answer and explanation
Take: \(\frac{(x+2)(x-5)}{(x-3)(x+4)}=1\)
Multiply both sides of the equation by \((x-3)(x+4)\) to get: \((x+2)(x-5)=(x-3)(x+4)\)
Expand and simplify both sides to get: \(x^2-3x-10=x^2+x-12\)
Subtract \(x^2\) from both sides to get: \(-3x-10=x-12\)
Add 12 to both sides to get: \(-3x+2=x\)
Add \(3x\) to both sides to get: \(2=4x\)
Solve: \(x = \frac{2}{4}=\frac{1}{2}\)
Answer: D
Cheers,
Brent
Re: If (x+2)(x-5)/(x-3)(x+4)=1, then x=
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28 Jan 2024, 15:04
28 Jan 2024, 15:04
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
