At first, we might not recognize that the given equation is a quadratic equation in disguise.

To see this, you must notice that (x^2)^2 = x^4

Now, if we let u = x^2, then we can rewrite the given equation.
We get: u^2 = 29u - 100
Rearrange to get: u^2 - 29u + 100 = 0
Factor to get: (u - 4)(u - 25) = 0
So, either u = 4, or u = 25

At this point, we can replace u with x^2 to get:
Either x^2 = 4, or x^2 = 25

If x^2 = 4, then x = 2 or x = -2
If x^2 = 25, then x = 5 or x = -5

So, there are 4 possible values of x: 2, -2, 5, and -5

Which of the following is NOT a product of three possible values of x :
I. -50
II. 25
III. 50

a. I only
b. II only
c. III only
d. I and II only
e. I and III only

I. 50
(-2)(5)(-5) = 50
Since 50 is possible, we can eliminate A, D and E

III. -50
(2)(5)(-5) = 50
Since -50 is possible, we can eliminate C

NOTE: At this point, we need not examine statement II, since we have already eliminated answer choices A, C, D and E

Answer:

RELATED VIDEO