I have to fix this one

If \(x+5>8\), \(x-2>1\), \(x<17\) and \(2x-7<5\), what is the range of possible values for x?
solving each inequality individually, we obtain \(x>3\), \(x>3\), \(x<17\) and \(x<6\). Hence the range of possible values for x is \(3<x<6\).

Morale of this question is "with any inequality, we should solve for upper and lower limit constraints"

As for \(x>13\), if \(x>3\) the two do not contradict each other

Thanks

Yes, but if the stem is incorrect.....the answer will be automatically incorrect

Could you please help me out with this? if x<17 and x<6 shouldn't x automatically be less than 17 for the upper range
so why can't it be 3<x<17?

If x+5 > 8, x−2 > 1, x < 17, and 2x−7 < 5, what is the range of possible values for x?
x + 5 > 8 => x > 3
x - 2 > 1 => x > 3
2x - 7 < 5 => 2x < 12 => x < 6
3 < x < 6 (Correct Answer: E)