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Re: If x² - 9 = 0, x² + xy - 18 = 0 nd x nd y r bth psitiv intgrs [#permalink]
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nurirachel wrote:
steveharvi wrote:
from the 1st equation, x^2 is 9, meaning x is either 3 or -3, from the 2nd equation since x^2 is 9, xy would be 9, y should be 3 or a -3 (x is either 3 or -3) . Option "E" only satisfies this, is this the correct way to approach this??


Carcass I agree, the correct answer is actually E, not B.


Yes, I fixed it in the first post

Yes it is E
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Re: If x² - 9 = 0, x² + xy - 18 = 0 nd x nd y r bth psitiv intgrs [#permalink]
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