GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If x and y are two positive integers and x + y = 5, then wha
[#permalink]
06 May 2019, 04:45
06 May 2019, 04:45
Expert Reply
00:00
Question Stats:
68% (00:36) correct
31% (00:56) wrong based on 29 sessions
Hide Show timer Statistics
If x and y are two positive integers and x + y = 5, then what is the probability that x equals 1?
(A) \(\frac{1}{2}\)
(B) \(\frac{1}{3}\)
(C) \(\frac{1}{4}\)
(D) \(\frac{1}{5}\)
(E) \(\frac{1}{6}\)
(A) \(\frac{1}{2}\)
(B) \(\frac{1}{3}\)
(C) \(\frac{1}{4}\)
(D) \(\frac{1}{5}\)
(E) \(\frac{1}{6}\)
Re: If x and y are two positive integers and x + y = 5, then wha
[#permalink]
13 Oct 2019, 02:06
13 Oct 2019, 02:06
The possible solutions are:
x y
1 4
2 3
3 2
4 1
Hence, x=1 is 1 case over 4 possible.
Answer C.
x y
1 4
2 3
3 2
4 1
Hence, x=1 is 1 case over 4 possible.
Answer C.
Moderator
Joined: 02 Jan 2020
Status:GRE Quant Tutor
Posts: 1115
Given Kudos: 9
Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
If x and y are two positive integers and x + y = 5, then wha
[#permalink]
31 Aug 2022, 00:31
31 Aug 2022, 00:31
1
Theory: Probability of Occurrence of and event P(E) is given by
P(E) = Number of Favorable Outcomes / Total Number of Outcomes
Given that x and y are two positive integers and x + y = 5 and we need to find the probability that x equals 1
Let's start by writing all the possible outcomes for x+y = 5, given that both x and y are positive integers. Posssible outcomes are
x = 1, y = 4
x = 2, y = 3
x = 3, y = 2
x = 4, y = 1
So, Total Number of Outcomes = 4
Number of Favorable outcomes in which x = 1 is 1 (x = 1, y = 4)
=> Probability (x=1) = (Favorable outcomes in which x = 1) / Total Number of Outcomes = \(\frac{1}{4}\)
So, Answer will be C.
Hope it helps!
P(E) = Number of Favorable Outcomes / Total Number of Outcomes
Given that x and y are two positive integers and x + y = 5 and we need to find the probability that x equals 1
Let's start by writing all the possible outcomes for x+y = 5, given that both x and y are positive integers. Posssible outcomes are
x = 1, y = 4
x = 2, y = 3
x = 3, y = 2
x = 4, y = 1
So, Total Number of Outcomes = 4
Number of Favorable outcomes in which x = 1 is 1 (x = 1, y = 4)
=> Probability (x=1) = (Favorable outcomes in which x = 1) / Total Number of Outcomes = \(\frac{1}{4}\)
So, Answer will be C.
Hope it helps!
