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If x is different from zero , which of the following must be true ?
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15 Apr 2022, 10:15
15 Apr 2022, 10:15
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75% (01:27) correct
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If x is different from zero , which of the following must be true ?
Indicate all that apply
A. \(\frac{1}{x}<x\)
B. \(-x<x\)
C. \(x^3<x^5\)
D. \(x<x^2+2\)
E. \(-|x|<|x|\)
Indicate all that apply
A. \(\frac{1}{x}<x\)
B. \(-x<x\)
C. \(x^3<x^5\)
D. \(x<x^2+2\)
E. \(-|x|<|x|\)
Part of the project: GRE Quantitative Reasoning Daily Challenge - (2022) EDITION
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
Re: If x is different from zero , which of the following must be true ?
[#permalink]
15 Apr 2022, 11:48
15 Apr 2022, 11:48
1
We are given that x is not equal to 0, so lets try x = 2 or -2,
A. 1/x<x ---> x = -2 ---> -0.5 < -2 , not true --> reject
B. −x<x ----> x = -2 ----> 2 < -2, not true --> reject
C. x^3 < x^5 ---> x = -2 ----> -8 < -32, not true --> reject
D. x<x^2+2 -----> x = -2 ---> -2 < 6, true. Lets try x = 2 as well -----> 2 < 6. Correct
E. −|x|<|x| ----> x = -2 ----> -2 < 2, true. Lets try x = 2, ---> -2 < 2. Correct
Hence options D and E are correct options and ans
A. 1/x<x ---> x = -2 ---> -0.5 < -2 , not true --> reject
B. −x<x ----> x = -2 ----> 2 < -2, not true --> reject
C. x^3 < x^5 ---> x = -2 ----> -8 < -32, not true --> reject
D. x<x^2+2 -----> x = -2 ---> -2 < 6, true. Lets try x = 2 as well -----> 2 < 6. Correct
E. −|x|<|x| ----> x = -2 ----> -2 < 2, true. Lets try x = 2, ---> -2 < 2. Correct
Hence options D and E are correct options and ans
Re: If x is different from zero , which of the following must be true ?
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03 Oct 2024, 10:33
03 Oct 2024, 10:33
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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